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FormatCode Code Formatter is based on serveral powerful syntax parser engines
so you can exactly control the appearance of your source code. Here is the code formatting demo of
FormatCode C/C++ Code Formatter to prove the ability of code formatting
functions of FormatCode:
#include <stdio.h>
#define l "=================================================="
#define m " "
int _(
float x,
float y){
return x>=0&&x<50&&y>=0&&y<20;}
int main (){
char a[2][20][51],c[9][4][51][51],d[100];
int e,f,g,h=0,i,j=0,k,b=0,n[9],o[9],p[9],x[9],y[9],q[9],r,s,t;
float u[9],v[9],w[9],z[9];
printf ("i%s\033Yppppppppppppppppppp1G0",l);
do sprintf(a[0][j],"%s",m,
sprintf (a[1][j],"%s",l));
while (++j<20);
scanf ("%d %d\n",&r,&s);
gets (d);
do {
sscanf (d,"%d %d %f %f %f %f %d %d %d",&o[b],&p[b],&u[b],&v[b],&w[b],
&z[b],&x[b],&y[b],&q[b],j=n[b]=i=0);
do do c[b][i][j][x[b]]=!
gets (c[b][i][j]);
while (++j<y[b]);
while (++i<q[b]+(j=0)||!++b);}
while (
gets (d)||(i=t=e=f=0));
do {
do strncpy(a[h][i],m,50);
while (++i<20||(i=0));
do if (t>=o[i]&&t<=p[i]&&!(k=j=0))
do do if (_(u[i]+k,v[i]+j))a[h][(
int )v[i]+j][(
int )u[i]+k]=c[i][n[i]][j][k];
while (++k<x[i]);
while (++j<y[i]+(k=0)||((++n[i]-q[i]||(n[i]=0)),u[i]+=w[i],v[i]+=z[i],0));
while (++i<b||(k=j=g=0));
do do if (a[1-h][j][k]!=a[h][j][k]){f-j&&
printf ("%dG0",j+1,e=0,g+=4);k&&e>k&&
printf ("0%d ",k,g+=4);k&&e<k&&k-e>1&&
printf ("%d ",k-e,g+=3);k&&e<k&&k-e==1&&
printf (" ",g++);
printf ("r%c",a[h][j][k],g+=2,e=k,f=j);}
while (++k<50);
while (++j<20+(k=0));
do printf ("1G0",g+=3,e=f=0);
while (g<s);h=1-h;}
while (++t<=r+(i=0));
return !
puts ("");}
#include <stdio.h>
#define l "=================================================="
#define m " "
int _(float x, float y)
{
return x >= 0 && x < 50 && y >= 0 && y < 20;
}
int main()
{
char a[2][20][51], c[9][4][51][51], d[100];
int e, f, g, h = 0, i, j = 0, k, b = 0, n[9], o[9], p[9], x[9],
y[9], q[9], r, s, t;
float u[9], v[9], w[9], z[9];
printf("i%s\033Yppppppppppppppppppp1G0", l);
do
sprintf(a[0][j], "%s", m, sprintf(a[1][j], "%s", l));
while (++j < 20);
scanf("%d %d\n", &r, &s);
gets(d);
do
{
sscanf(d, "%d %d %f %f %f %f %d %d %d", &o[b], &p[b], &u[b],
&v[b], &w[b], &z[b], &x[b], &y[b], &q[b], j = n[b] = i = 0);
do
do
c[b][i][j][x[b]] = !gets(c[b][i][j]);
while (++j < y[b]);
while (++i < q[b] + (j = 0) || !++b);
}
while (gets(d) || (i = t = e = f = 0));
do
{
do
strncpy(a[h][i], m, 50);
while (++i < 20 || (i = 0));
do
if (t >= o[i] && t <= p[i] && !(k = j = 0))
do
do
if (_(u[i] + k, v[i] + j))
a[h][(int)v[i] + j][(int)u[i] + k] = c[i][n[i]][j][k];
while (++k < x[i]);
while (++j < y[i] + (k = 0) || ((++n[i] - q[i] || (n[i] = 0)),
u[i] += w[i], v[i] += z[i], 0));
while (++i < b || (k = j = g = 0));
do
do
if (a[1-h][j][k] != a[h][j][k])
{
f - j && printf("%dG0", j + 1, e = 0, g += 4);
k && e > k && printf("0%d ", k, g += 4);
k && e < k && k - e > 1 && printf("%d ", k - e, g += 3);
k && e < k && k - e == 1 && printf(" ", g++);
printf("r%c", a[h][j][k], g += 2, e = k, f = j);
}
while (++k < 50);
while (++j < 20+(k = 0));
do
printf("1G0", g += 3, e = f = 0);
while (g < s);
h = 1-h;
}
while (++t <= r + (i = 0));
return !puts("");
}
Click here to preview the C/C++ Code Formatting Demo 1, C/C++ Code Formatting Demo 3 and C/C++ Code Formatting Demo 4.
 With FormatCode C++ Code Formatters, you can format and transform any foreign C/C++ source code to meet your preferred coding style or any common code convention in several seconds!
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